4x^2-20x+32=0

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Solution for 4x^2-20x+32=0 equation: 



4x^2-20x+32=0

a = 4; b = -20; c = +32;
Δ = b2-4ac
Δ = -202-4·4·32
Δ = -112
Delta is less than zero, so there is no solution for the equation

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